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5x^2-14x=13
We move all terms to the left:
5x^2-14x-(13)=0
a = 5; b = -14; c = -13;
Δ = b2-4ac
Δ = -142-4·5·(-13)
Δ = 456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{456}=\sqrt{4*114}=\sqrt{4}*\sqrt{114}=2\sqrt{114}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{114}}{2*5}=\frac{14-2\sqrt{114}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{114}}{2*5}=\frac{14+2\sqrt{114}}{10} $
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